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Code Block
languagejs
$Xml.Load('for $c in //Person                         ' +
   'where $c/Surname                                  ' +
   'return                                            ' +
   '  <Person>                                        ' +
   '    <Name>{ $c/Name }</Name>                      ' +
   '  <Person>                                        ');

See Also

  • XPath+and+XQuery